Any question answered...

It's a very small change in axle distance due to cosines and stuff, but less difference than there is between new chain and part worn

Okay so I reckon that could work ; what I had not precised (and has its importance) is that the hub would be white industries ENO eccentric which does allow a solid bit of play for adjustments (but brakes adjustments would have to be taken into account to).

Thanks for the help!

A bit? It's sodding binning it down in Sa Calobra just now.

It was pissing down the week we were in Mallorca last year (roughly same time)

Don't use slack very often but have a client that does asking us to join their workspace. To give you an idea of how little we use it... how do I accept without entering a password? If I click the link in their email it takes me to a 'join the slack workspace Clientblahblah' with boxes for name/display name and password (no email address or account name or anything to link to it). I'm already signed in on the browser and have the app open on the desktop, also signed in. I'm super cagey about phishing these days so the idea of entering a password seems odd to me in this situation.

Basically is there a way I can paste or type the workspace domain somewhere to join into my signed in browser/app?

You should be able to use the diode check feature, also known as continuity check - it's the yellow segment at around the 5 o'clock mark. It should make a buzzing sound if there's a low resistance, indicating continuity.
If you do want to use the resistance method, the 2M range is not a good idea - that will only measure for you in units of, I guess, 10 kiloohm. A considerable resistance would still show up as 0 ohm.
Better to use a lower range, probably 200 would be fine. I am not an electrician, but I would be worried if your house wiring had a resistance greater than 200 ohm!

fuuuk, scaaary looking....

Also: a drillium frame of all things, but then still keeping that monstrosity of a saddle??

How much thicker than light is wind? 10 x thicker? I can see a gap in my door frame, light enters, but will wind?

If you can see a gap, air will be coming through; use foam tape or something to block it up?

.

^
^
This.
Light a candle, hold it up to the gap and see what happens to the flame.
ETA: Or just light a candle, its Halloween.

Where to go for a holiday the first week of December?

Anywhere but Berlin.

Is Berlin closed for the first week of December?

By this point, I, too, had developed a vague aversion to the trip, an inability to recall why I’d proposed Antarctica in the first place. The idea of “seeing it before it melts” was dismal and self-cancelling: why not just wait for it to melt and cross itself off the list of travel destinations? I was also put off by the seventh continent’s status as a trophy, too remote and expensive for the common tourist to set foot on. It was true that there were extraordinary birds to be seen, not just penguins but oddities like the snowy sheathbill and the world’s southernmost-breeding songbird, the South Georgia pipit. But the number of Antarctic species is fairly small, and I’d already reconciled myself to never seeing every bird species in the world. The best reason I could think of for going to Antarctica was that it was absolutely not the kind of thing the Californian and I did; we’d learned that our ideal getaway lasts three days. I thought that if she and I were at sea for three weeks, with no possibility of escape, we might discover new capacities in ourselves. We would do a thing together that we would then, for the rest of our lives, have done together.

How much thicker than light is wind? 10 x thicker?

People routinely use light to inspect for gaps of the order of 10μm

Let's say you have a 13m.s^-1 (30mph) wind pushing on the outside of the door, generating a dynamic pressure of about 100Pa
If the gap is 2m high and 5cm deep but only 10μm wide, the flow will only be about 10cm³.s^-1. In a fairly small room, that flow rate is about one air change per month.

Is Berlin closed for the first week of December?

No, it's just going to rain a lot.

Think someone will still smidsy?

Isn’t this so bright it would distract oncoming?

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It does look brutally bright, but I wonder whether it looks as bright in real life... also what I usually think is that I want the light to be as bright as possible, I'll just angle it down more - you can never see too much right in front of you.

My problem is the external battery pack: I am an incredibly lazy human being, so I only get lights that I can clip in and out with one movement. I would not want to have fiddle with a battery back on my top tube every time I lock it up.

Random Chinese LED ratings are not to be taken at face value.

@useless and @danstuff helped out with this before back here

but i'm still struggling.

I want to approximate a hemisphere but I'm just reducing by a fixed amount, whereas I need to reduce by a little bit at first and then gradually more and more.
My parameters are thickness of material, and diameter or radius of the biggest bottom circle.

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So you want the upper edge of each circle to be exactly on the hemisphere?

See this (sorry for the quick and dirty sketch), where h is the height of all the discs up to that point (including the one you want to find the radius of), and r is the radius of the hemisphere you're looking for.

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So you want the upper edge of each circle to be exactly on the hemisphere?

Yes, ideally, although anything approximating that would be good

Well see the sketch, with that formula, you can calculate it to whatever precision you require, certainly with Excel. :)