If an aluminium tube is 42mm OD at room temperature, what would the OD be when heated uniformly to 120 deg C?
You can calculate this for yourself, but 42.1mm. α=2.1 to 2.4×10-5.K-1 depending on which aluminium alloy ΔT=100K 42×(1+(2.1×10-5×100))=42.09 42×(1+(2.4×10-5×100))=42.10
@PhilDAS started
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If an aluminium tube is 42mm OD at room temperature, what would the OD be when heated uniformly to 120 deg C?