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these are the best according to moneysavingexpert. http://www.bestforeignexchange.com/
order online and you can pick it up in london the same day -
^ You didn't even know that? :D
Flights and accom paid for by work. The only input I have had is booking a travel request on our intranet to Geneva and buy ski gear.
these are the best according to moneysavingexpert. http://www.bestforeignexchange.com/
order online and you can pick it up in london the same dayCheers, I will have a look. I seem to vaguely recall the RBS JUST over Blackfriars having a euro dispensing atm. Will wander over at lunch.
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Always black cables.
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cables with wire in them, ask at your lbs..
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these are the best according to moneysavingexpert. http://www.bestforeignexchange.com/
order online and you can pick it up in london the same dayseconded.
Mrs P is very "frugal" and she always insists we use them.
FWIW, we go over to Europe twice a year, and take about 500 euros cash each time. Split it up in lots of wallets / purses in case you lose it / get robbed. Never had any problems.
use a atm/ credit card for emergency cash and large purchases. You might want to let your cc provider know you are going - we had a cc purchase refused in Spain because the bank thought it was stolen. Mrs P went ballistic with the bank when we got home.
Have fun, you lucky thing.
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do you mean "momentum"?
He means kinetic energy.Inertia expresses an object's resistance to a change in state of motion (speed and/or direction).
Momentum is the product of an object and it's velocity. This implies vectors, so an object moving in a straight line has momentum in its direction of travel but none in vectors normal to the direction of travel.
An object's moment of inertia is an expression of the torque required to achieve a change in speed of rotation.
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That doesn't seem like a crazy amount of movement - everything still engages as it should?
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do you mean "momentum"?
No, as Emyr points out, an inertial object doesn't have momentum until an impulse causes it to have some velocity.
A bicycle in motion has two kinds of momentum; first the product of the total mass and the velocity, second the product of the moments of inertia of the various rotating parts and their respective angular velocities.
Because the periphery of a wheel never goes faster than the forward velocity, the absolute worst case (or best, if you're in a freewheeling competition) is that the total momentum of the wheels is double what the same mass on a non-rotating part contributes at any given velocity.
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It appears my freehub body may need replacing as the body seems to be moving when the cassette isn't in motion - here
Surely this shouldn't happen after 3 months use?!?!
This happens with some some old screw-on freewheels (mine does it) and it's not a big deal, but I've not seen it with a freehub. Since the bearing surface inside the freehub isn't turning when the cassette is stationary, does it imply that it's a problem on the non-drive side?
Edit: no, it doesn't. If the splines on the hub body aren't dead-centre then the freehub will oscillate like that when the wheel turns.
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Because the periphery of a wheel never goes faster than the forward velocity
[[citation needed]]
velocity of any point on the wheel varies in the range
v plus (v*rPoint/rMax)
to
v minus (v*rPoint/rMax)
according to sin(θ).
Where rMax is the radius at the point of contact and v is the forward velocity of the bicycle.
the total momentum of the wheels is double what the same mass on a non-rotating part contributes at any given velocity.
[[citation needed]]
What kind of wheel obeys I = m*r^2 yet gives such a simple result as "double"?
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v - (v*rPoint/rMax)?
[[citation needed]]
velocity of any point on the wheel varies in the range
v + (v*rPoint/rMax)
to
v - (v*rPoint/rMax)
according to sin(θ).
Where rMax is the radius at the point of contact and v is the forward velocity of the bicycle.
[[citation needed]]
What kind of wheel obeys I = m*r^2 yet gives such a simple result as "double"?
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v = v*
edit - but there is no v*, that was multiplication. I am stupid, ignore me.
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The top of the wheel moves forward at 2v, the bottom is stationary.
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v - (v*rPoint/rMax)?
I was trying to keep consistency between the forwards and backwards states, but essentially the hub axis is at rPoint = 0 so this simplifies to v, whereas at the contact point v = 0.
points must go faster than V so that Σ vPoint tends to Σv.
Points at rPoint = rMax/2 have forward velocities between 0.5v and 1.5v
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@Emyr:
I was on the phone, so shoot me.Since angular momentum and linear momentum aren't even in the same units, what I wrote was clearly bollocks.
What I was aiming at was that treating the wheel as both a lump of material which has to travel with the bike and as flywheel, the conversion of that angular momentum back into linear momentum (by taking off force at the tyre contact) can't provide a greater impulse than just carrying the same mass as an extra lump. I'm less convinced of that than I was earlier, but I don't have the time at the moment to prove it one way or the other. If you want to have a crack at it, feel free.
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^^Drops, lower centre of gravity = better cornering. Short(ish) cranks would be your friends too.......
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@carson
^ You didn't even know that? :D