What is a simple way of explaining why sin((pi/2)-θ)=cosθ?
I think it's easy to explain if you draw it, with the hypotenuse as the radius of circle centred on x=y=0, you can then see how (π/2)-θ relates to θ making it obvious why the sin of the one is equal to the cos of the other.
I think it's easy to explain if you draw it, with the hypotenuse as the radius of circle centred on x=y=0, you can then see how (π/2)-θ relates to θ making it obvious why the sin of the one is equal to the cos of the other.