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@BareNecessities
Sorry, missed both your replies as I'd gone to bed. Thanks for the explanation, but It wasn't the basic big disc/rim = more leverage = greater force part of the design that I was unclear on*. My query was whereabouts these forces were being applied to the fork legs.
*I'm aware that I could well be talking to a physicist here, whilst my degree is in photography ;-)
Quoted from Jobst Brandt ( Admittedly about 7 years ago! )
"With rim brakes forks are loaded in bending at the fork crown that similarly supports road shock, while a disc brake places an equal bending torque at the tip of the fork and only on one blade. The fork can only be slender and light because it carries no bending loads at the dropout. With disc brakes forks would require a substantial increase in cross section (and weight) and brake would be heavier".