I was pretty sure the original rule was 2 of the original 3 players. but not the same two players every time, so A,B,C then A,B,D then A,C,E is fine, as they always have 2 of A,B,C
I might be wrong though, I'd have to dredge out the rule, which I can't be bothered to right now.
I was pretty sure the original rule was 2 of the original 3 players. but not the same two players every time, so A,B,C then A,B,D then A,C,E is fine, as they always have 2 of A,B,C
I might be wrong though, I'd have to dredge out the rule, which I can't be bothered to right now.