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@TheBrick(Tommy)
f(x,y)=x^2−2xy+2(y^2)−6y+3
\frac{\partial f}{\partial x}= 2x-2y
= 2(x-y)
\frac{\partial f}{\partial y}=-2x+4y-6
=2(x+2y-3)
What is this saying?