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ChainBreaker
NotThamesWater
Seeing as I had it fired up already to write a bunch of equations in Latex format for me:
Torque due to Uniform Mass:
(1)
Torque due to Point Mass at p:
The total torque:
The force equation:
Expressing forces in terms of the angle (θ):
Solving for F [edit - corrected]
m is the uniform mass of the lever.
n is the point mass added at distance p from the pivot.
l is the length of the lever.
g is the gravitational acceleration.
For an IWF Men's Olympic bar, with a 20kg plate, at 45° & 60° (on earth...)
F_45 ≈ 361.36N ≈ 36kg
[edit - corrected]
(8)
F_60 ≈ 250.68N ≈ 25kg