Any maths buffs?

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Greenbank

Might just be simpler to do:

p = { p₁, p₂, ... , p_t }

As that defines both p and t in one go.

I'm rusty though.

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NotThamesWater in reply to @Greenbank

That does make sense though.

I have corrected it so that P = {p1, p2 ...}

The second bit is to make it clear that t must be 1, 2, 3 . . . t with no missing numbers, (otherwise things break later).

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