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  • There doesn't appear to be any force pushing the rider to make a wider turn, this obviously happens on the flat and can also happen on less steeply banked tracks.

    Would R(v) be the force at play?

  • I'd have to re-read the accompanying text next to the figures and even then I'm not sure I could answer you.

  • Objects in equilibrium (ie no net forces) continue to go in the direction and speed they were already heading. Forces are only needed to change direction.

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