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lynx
@Greenbank
If there's a 7.6% chance of a random friend having had it then there's a 92.4% chance of a random friend having not had it.
So the probability of two random friends both having not had it is 92.4% * 92.4% = 85.4% (1dp)
For 10 friends picked at random never to have it it would be 92.4% ^ 10 = 45.4% (1dp)
For 100 friends 0.0369% (3sf)
For 200 friends it's below 0.00002% (1sf)
For 500 friends it's 0.0000000000000007% (1sf)
For 1000 friends multiply the above result against itself. It's vanishingly small.