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Cheers @gbj_tester and @Thrustvector.
50g is about a large mouthful of water or the reduction in weight from an Dura-Ace component to a 105. I was curious to work out the actual impact in energy expenditure of a reduction in the mass moved by the rider. More complex a question than I reckoned.
Thanks for replying. I’m trying to work out the energy impact of using normal inner tubes vs. light weight inner tubes (combined weight difference of 50g) on, e.g., Campenaerts’ hour record of 55km. It’s for illustrative purposes rather than a formal inquiry, so don’t need to overly complicate it.
Edit- what I’ve done so far:
W=F*d
W=(m*a)d . I’m not sure how to work out or around the acceleration.
W=[m(v-v0/t)]d
W=[.05kg(15.28m/s-0m/s /3600s)55000m
W=[.05kg(.004244m/s^2)]55000m
W=.000212N*55000m
W=11.66J
...?