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  • How can I calculate the work necessary to move .05kg over 55km in one hour? It’s driving me up a wall, especially knowing it’s not complicated but I just don’t see it.

  • 55 km horizontally in a vacuum? Zero work done.

    55 km horizontally in not a vacuum? You need to know wind resistance of your object, and the speed it moves, and so on.

  • Thanks for replying. I’m trying to work out the energy impact of using normal inner tubes vs. light weight inner tubes (combined weight difference of 50g) on, e.g., Campenaerts’ hour record of 55km. It’s for illustrative purposes rather than a formal inquiry, so don’t need to overly complicate it.

    Edit- what I’ve done so far:
    W=F*d
    W=(m*a)d . I’m not sure how to work out or around the acceleration.
    W=[m(v-v0/t)]d
    W=[.05kg(15.28m/s-0m/s /3600s)55000m
    W=[.05kg(.004244m/s^2)]55000m
    W=.000212N*55000m
    W=11.66J
    ...?

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