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if the difference will very likely be lost in the rounding, isn't the answer 'no'?
No, because "very likely" is not the same as "definitely". At some point, there is going to be an edge case where the correct solution is spokes of different lengths even when the length increment of available spokes is so large compared with the difference in calculated ideal length.
gbj_tester
Thanks for the answer, but if the difference will very likely be lost in the rounding, isn't the answer 'no'?