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The point isn't the 20bar. It's the alleged 150bar (where the fuck are you even going to do that?), which means it's been tested up to that amount and deemed the maximum safe net give or take.
The difference between 20bar and 150 is quite significant. Any way of calculating that exponentially? (mathematics makes my brain BSOD)Pretty sure there's encyclopedic amounts of paper to fill out for that amount of contained pressure and use.
I can see how a downtube could take 20bar (see below), but can't see how it's connected to the toptube reservoir? If it goes via the headtube, then there must be a clever junction to stop the air blowing through the headset bearings.
Force exerted on a inner surface of steel tube, 40mm diameter @ 20Bar = 20*10^6 * 0.04 * pi = 25kN. Tensile strength of Reynolds 853 is 1400MPa, so in theory, a wall thickness of t = 25kN / (1400MPa * tube length 1m) = 0.2mm should be able to contain 20bar. Please correct me if I'm wrong.