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  • I’m guessing it’ll be (temperature - the mean temperature)/standard deviation.

    So if you had historically temperature for 5 days — let’s say 24, 25, 26, 26, 25. That’ll give you an average of 25.2 and a standard deviation of 0.7. Therefore if they had a 30 degree day that’d give a z-stat of (30-25.2)/0.7 = 6.9.

    But isn’t this just a long winded way of saying it’s warm and the conditions will be good?

  • I'm talking about wind conditions rather than temperature... using mywindsock.com along the entire route.

    I have had considerable assistance from Ben Norbury (himself an accomplished long distance TTer) who runs that most excellent website. Unfortunately he doesn't actually control the wind, which would be even more helpful.

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