I’m guessing it’ll be (temperature - the mean temperature)/standard deviation.
So if you had historically temperature for 5 days — let’s say 24, 25, 26, 26, 25. That’ll give you an average of 25.2 and a standard deviation of 0.7. Therefore if they had a 30 degree day that’d give a z-stat of (30-25.2)/0.7 = 6.9.
But isn’t this just a long winded way of saying it’s warm and the conditions will be good?
I’m guessing it’ll be (temperature - the mean temperature)/standard deviation.
So if you had historically temperature for 5 days — let’s say 24, 25, 26, 26, 25. That’ll give you an average of 25.2 and a standard deviation of 0.7. Therefore if they had a 30 degree day that’d give a z-stat of (30-25.2)/0.7 = 6.9.
But isn’t this just a long winded way of saying it’s warm and the conditions will be good?