I think that is
It's the same maths as j-bend spokes; locate the two ends in Cartesian space and do Pythagorus to the difference.
If the two ends are located at x1y1z1 and x2y2z2 then
Spoke length2 = (x1-x2)2+(y1-y2)2+(z1-z2)2
That what I did but with a short cut I'd didn't explain. What u did only works with a drawing otherwise you have to use the proper method you gave.
@cycleclinic started
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It's the same maths as j-bend spokes; locate the two ends in Cartesian space and do Pythagorus to the difference.
If the two ends are located at x1y1z1 and x2y2z2 then
Spoke length2 = (x1-x2)2+(y1-y2)2+(z1-z2)2