don't be silly, only one multiplication needed:
B = 1 + (B/2) B - (B/2) = 1 (B/2) = 1 3 * (B/2) = 3
That did occur to me, after posting. I think I instinctively wanted the subtraction to be integral, or something.
It's not like I'm worried about the computational complexity or anything.
@mashton started
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don't be silly, only one multiplication needed:
B = 1 + (B/2)
B - (B/2) = 1
(B/2) = 1
3 * (B/2) = 3