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No, an iPhone charger is 0,5 amp if I remember correctly. It's the iPad charger that's 1 amp, but that's not relevant to your question.
In reality this means if you plug a battery in that's completely flat it's gonna charge at 5 volt and 1 amp for the first second of charging. It charges at 5 volt 0 amp when the battery is full (cause you can't charge a full battery). And in between your amperage (current) slowly drops, that's why your phone charges pretty quickly to 30%, but the closer you get to 100%, the slower it goes.
When you leave on your lights you are making it harder for yourself, when there is no connection between the 2 leads on your hub there is no current being drawn from your hub, there's only a voltage of 6 volt. Current*voltage=power so when your current is zero the power you need to put into your hub is zero.
When you put a 0,5 amp light on your hub and turn it on, your current is 0,5A and voltage 6V resulting in 3Watt (0,5*6=3) of power it uses, so you'll have to put out 3Watt of extra power through your legs.
Back to the iPhone (or di2) charger, when the battery is fully charged the power going to the battery is zero since there is no current, so leaving it plugged in doesn't result in extra Watts needed from your legs.
But isn't the voltage and current drawn by a charger always going to be the same?
Ie, an iphone charges at like 5v and 1 amp right?
So if you plug it in when the battery is flat and charge it until it's full and then unplug it'll have drawn 5v at 1 amp for say an hour or so.
If you leave it plugged in all the time and the charger maintains the battery at 100% it'll draw 5v/1amp all the time.
No?
I have kind of wondered whether I make things harder for myself by leaving my lights on all the time. I thought that in setups like mine where the on/off switch is on the light, the hub always provided power and therefor had the same resistance. You had to have a switch on the hub (is this even a thing?) that turned power generation on and off to get a difference in the resistance.