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Sounds reasonable to me. You have assumed you have a minimal helix angle, but that seems like a good assumption to make. I'd get yourself some spare too of course, just in case...
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21.4cm circumference, 0.6cm rope would need 210/.6=350 turns at 21.4cm each=7490/100=75m?
Surface area of pipe = 210cm * pi * 6.8cm = 4486.2 cm^2
So if rope diameter is 0.6cm then you'd need at least 4486.2cm^2 / 0.6cm = 7477cm of it.
I hope the rope is a bit stretchy as 6.8cm is the inner diameter of the coil.
The outer diameter (pipe+rope+rope) will now be 6.8+0.6+0.6 = 8cm.
210cm * pi * 8cm / 0.6cm = 8796cm per pipe
Guess you'll have a better idea after you've done one...
hamrack
Greenbank
@Dammit
21.4cm circumference, 0.6cm rope would need 210/.6=350 turns at 21.4cm each=7490/100=75m?