"20 grams of drag reduction means 10 seconds at 25 mph over 40 kilometers"
0.1 lbs (50 g) of drag (at 30 mph) = 0.5 s/km = 5 W = 0.005 m^2 CdA = 0.0005 Crr
If that's right, then my 12hr TT will be 11 hours and 58 minutes :)
@hippy started
London Fixed Gear and Single-Speed is a community of predominantly fixed gear and single-speed cyclists in and around London, UK.
This site is supported almost exclusively by donations. Please consider donating a small amount regularly.
"20 grams of drag reduction means 10 seconds at 25 mph over 40 kilometers"
0.1 lbs (50 g) of drag (at 30 mph) = 0.5 s/km = 5 W = 0.005 m^2 CdA = 0.0005 Crr
If that's right, then my 12hr TT will be 11 hours and 58 minutes :)